Issue #10714 - Each expression stores its operator as a string, and default serialization is [operator, serialize(child1), ...] - Custom implementations of `serialize` for Expression types that don't follow the pattern - expression::Value -> mbgl::Value converter - node_expression bindings to expose `serialize`
51 lines
1.5 KiB
C++
51 lines
1.5 KiB
C++
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#pragma once
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#include <mbgl/style/expression/expression.hpp>
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#include <mbgl/style/expression/parsing_context.hpp>
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#include <mbgl/style/conversion.hpp>
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#include <mbgl/util/range.hpp>
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#include <memory>
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#include <map>
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namespace mbgl {
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namespace style {
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namespace expression {
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class Step : public Expression {
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public:
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Step(const type::Type& type_,
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std::unique_ptr<Expression> input_,
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std::map<double, std::unique_ptr<Expression>> stops_
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) : Expression(type_),
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input(std::move(input_)),
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stops(std::move(stops_))
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{}
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EvaluationResult evaluate(const EvaluationContext& params) const override;
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void eachChild(const std::function<void(const Expression&)>& visit) const override;
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void eachStop(const std::function<void(double, const Expression&)>& visit) const;
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const std::unique_ptr<Expression>& getInput() const { return input; }
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Range<float> getCoveringStops(const double lower, const double upper) const;
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bool operator==(const Expression& e) const override;
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std::vector<optional<Value>> possibleOutputs() const override;
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static ParseResult parse(const mbgl::style::conversion::Convertible& value, ParsingContext& ctx);
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mbgl::Value serialize() const override;
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std::string getOperator() const override { return "step"; }
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private:
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const std::unique_ptr<Expression> input;
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const std::map<double, std::unique_ptr<Expression>> stops;
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};
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} // namespace expression
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} // namespace style
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} // namespace mbgl
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